• :00Days
  • :00Hours
  • :00Mins
  • 00Seconds
A new era for learning is coming soonSign up for free
Log In Start studying!

Select your language

Suggested languages for you:
Answers without the blur. Sign up and see all textbooks for free! Illustration

Q11P

Expert-verified
Fundamentals Of Physics
Found in: Page 740

Answers without the blur.

Just sign up for free and you're in.

Illustration

Short Answer

In Fig. 25-29, find the equivalent capacitance of the combination. Assume that C1=10.0μF, C2=5.00μF and C3=4.00μF

The equivalent capacitance of the combination is 3.16 μF

See the step by step solution

Step by Step Solution

Step 1: Given

The capacitance C1=10.0 μF

The capacitance C2=5.00 μF

The capacitance C3=4.00 μF

Step 2: Determining the concept

Using the equation 25-19, find the equivalent capacitance of C1 and C2. Then using 25-20, find the equivalent capacitance of the given combination.

Formulae are as follows:

Capacitors in series combination,

1Ceq=1C1+1C2

Capacitors in parallel combination,

Ceq=C1+C2

Step 3: Determining the equivalent capacitance of the combination

From Figure, it can be seen that, C1 and C2 are connected in parallel. Therefore,

From the equation 25-19, the equivalent capacitance is given by,

C12=C1+C2

From the above figure, we can see that C12 and C3 are connected in a series.

From the equation 25-20, the equivalent capacitance is given by,

1Ceq=1C12+1C3

Therefore,

Ceq=C12C3C12+C3

Therefore,

Ceq=10.0μF+5.00 μF×4.00μF10.0μF+5.00 μF+4.00μFCeq=3.16μF

Hence, the equivalent capacitance of the combination is 3.16 μF

Therefore, by using the formula of capacitors in series and parallel combinations, equivalent capacitance can be determined.

Recommended explanations on Physics Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.