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Found in: Page 794

### Fundamentals Of Physics

Book edition 10th Edition
Author(s) David Halliday
Pages 1328 pages
ISBN 9781118230718

# Cap-monster maze. In Fig. 27-22, all the capacitors have a capacitance of ${\mathbf{60}}{\mathbf{}}{\mathbf{\mu C}}$, and all the batteries have an emf of 10 V. What is the charge on capacitor C? (If you can find the proper loop through this maze, you can answer the question with a few seconds of mental calculation).

The charge on capacitor C is $60\mathrm{\mu C}$.

See the step by step solution

## Step 1: Given

$\mathrm{V}=10\mathrm{V}\phantom{\rule{0ex}{0ex}}\mathrm{C}=6.0\mathrm{\mu F}$

## Step 2: Determining the concept

Here, use the formula for the charge in terms of the voltage and the capacitor. When the capacitors are connected in series with battery, voltage remains same through the capacitors.

Formulae are as follow:

$\mathrm{q}=\mathrm{CV}$

Where, C is capacitance, V is potential difference, q is charge

## Step 3: Determining the charge on capacitor C

Consider the loop as shown in figure 27-22 in which the capacitor C is connected in series with the battery shown by the path in red.

So, the voltage across capacitor C is 10 V

Now, the charge is as follow,

$\mathrm{q}=\mathrm{CV}\phantom{\rule{0ex}{0ex}}\mathrm{q}=6.0×10\phantom{\rule{0ex}{0ex}}\mathrm{q}=60\mathrm{\mu C}$

Hence, the charge on capacitor C is $60\mathrm{\mu C}$

Therefore, first find the voltage through the capacitors. From that, find the charge through the capacitors.