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Q19P

Expert-verifiedFound in: Page 796

Book edition
10th Edition

Author(s)
David Halliday

Pages
1328 pages

ISBN
9781118230718

**A total resistance of 3.00 Ω is to be produced by connecting an unknown resistance to a 12.0 Ω resistance.**

**What must be the value of the unknown resistance, and****(b) Should it be connected in series or in parallel?**

- The value of the unknown resistance is ${R}^{\text{'}}=4.00\text{\Omega}$
- The unknown resistance should be connected in parallel.

${R}_{eq}=3.00\text{\Omega}\phantom{\rule{0ex}{0ex}}R=12.0\text{\Omega}$

**It can be predicted whether the unknown resistance is connected parallel or series from the given values. Then using the formula for corresponding equivalent resistance, find ****the value of the unknown resistance.**

Formulae are as follow:

$\frac{1}{{R}_{eq}}=\frac{1}{R}+\frac{1}{{R}^{\text{'}}}$

Where, *R* is resistance.

Let the unknown resistance connected be R’.

From the given values, we can write that ${R}_{eq}<R.$

This implies that the unknown resistance is connected in parallel.

Hence,

$\frac{1}{{R}_{eq}}=\frac{1}{R}+\frac{1}{{R}^{\text{'}}}\phantom{\rule{0ex}{0ex}}\therefore {R}_{eq}=\frac{R{R}^{\text{'}}}{R+{R}^{\text{'}}}\phantom{\rule{0ex}{0ex}}3=\frac{12{R}^{\text{'}}}{12+{R}^{\text{'}}}\phantom{\rule{0ex}{0ex}}36+3R\text{'}=12R\text{'}\phantom{\rule{0ex}{0ex}}{R}^{\text{'}}=4.00\text{\Omega}$

Hence, the value of the unknown resistance is ${R}^{\text{'}}=4.00\text{\Omega}$

From part a),

it can be concluded that the unknown resistance should be connected in parallel.

Hence, the unknown resistance should be connected in parallel.

Therefore, by using the formula for corresponding equivalent resistance, unknown resistance can be determined.

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