• :00Days
• :00Hours
• :00Mins
• 00Seconds
A new era for learning is coming soon

Suggested languages for you:

Americas

Europe

Q14P

Expert-verified
Found in: Page 766

### Fundamentals Of Physics

Book edition 10th Edition
Author(s) David Halliday
Pages 1328 pages
ISBN 9781118230718

# A human being can be electrocuted if a current as small as 50mA passes near the heart. An electrician working with sweaty hands makes good contact with the two conductors he is holding, one in each hand. If his resistance is ${\mathbf{2000}}{\mathbf{\Omega }}$, what might the fatal voltage be?

The value of the fatal voltage is 100V.

See the step by step solution

## Step 1: The given data

1. Current passing near the heart is, l = 50mA or 0.050 A
2. Resistance, $\mathrm{R}=2000\mathrm{\Omega }$

## Step 2: Understanding the concept of the Ohm’s Law

Ohm’s law states that the potential difference is directly proportional to the current and the constant of proportionality is called resistance.

We can find the fatal voltage by substituting the given values of the current and the resistance in the formula for Ohm’s law.

Formula:

The voltage equation from Ohm’s law, V = lR …(i)

Here, V is the potential difference, l is current, R and is resistance.

## Step 3: Calculation of the fatal voltage

Using the given data in equation (i), we can get the value of the fatal voltage as follows:

$\mathrm{V}=\left(0.050\mathrm{A}\right)\left(2000\mathrm{\Omega }\right)\phantom{\rule{0ex}{0ex}}=100\mathrm{V}$

Therefore, the fatal voltage is 100V.