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Fundamentals Of Physics
Found in: Page 1115

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Short Answer

If, in a two-slit interference pattern, there are8 bright fringes within the first side peak of the diffraction envelope and diffraction minima coincide with two-slit interference maxima, then what is the ratio of slit separation to slit width?

The ratio of the slit separation to the slit width is 9:1 .

See the step by step solution

Step by Step Solution

Step 1: Given data

In a two-slit interference pattern, there are 8 bright fringes within the first side peak of the diffraction envelope.

Step 2: Diffraction and interference from a double slit

The angular distance of the mth order diffraction minima is given by

asinθ=mλ …(i)

Here, λ is the wavelength of the incident light and a is the slit width.

The angular distance of the nth order interference maxima is given by

dsinθ=nλ …(ii)

Here, λis the wavelength of the incident light and d is the separation between the two slits.

Step 3: Determining the ratio of the slit separation to the slit width

The 9th interference maxima coincide with the 1stdiffraction minima. From equations (i) and (ii) the angular distance of the 1st diffraction minima and the 9thinterference maxima is

dsinθ=9λasinθ=λ

Divide the two equations to get

da=91

Thus, the required ratio is 9:1 .

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