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Fundamentals Of Physics
Found in: Page 1002

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Short Answer

A black, totally absorbing piece of cardboard of area A = 2.0 cm2 intercepts light with an intensity of 110 W/m2 from a camera strobe light. What radiation pressure is produced on the cardboard by the light?

The radiation pressure is, Pr=3.3×10-8 Pa.

See the step by step solution

Step by Step Solution

Step 1: Given data

Area of cardboard, A=2 cm2.

Intensity, I = 10 W/m2.

Step 2: Determining the concept

The radiation pressure formula is for the total absorption of radiation. First, find the force on the surface due to radiation, and substituting this value and the area of the surface, calculate the radiation pressure of the light bulb. When electromagnetic radiation of intensity I is incident on a perfectly reflective surface, the radiation pressure P exerted on the surface is given by, , where c is the speed of light.

Step 3: Determining the radiation pressure produced on the cardboard by the light

If the radiation is totally absorbed by the surface, the force is,


Here I is the intensity of radiation, and A is the area of the surface perpendicular to the path of the radiation.

The intensity I is related to the power of the bulb P as,


Where, A is the area of the cardboard.

The radiation pressure Pr is the force per unit area, and it can be calculated as,


Substitute the values in the expression, and we get,

Pr=10 w3×108m/s=3.3×10-8 Pa

Therefore, the radiation pressure pr is 3.3×10-8 Pa.

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