A nuclear reactor is operating at a certain power level, with its multiplication factor k adjusted to unity. If the control rods are used to reduce the power output of the reactor to 25% of its former value, is the multiplication factor now a little less than unity, substantially less than unity, or still equal to unity?
The multiplication factor for power output to 25% of its former value remains unity.
The ratio of the number of neutrons for a particular generation of power to the number of neutrons initially for the same power generation is called the multiplication factor.
The multiplication factor for power output to 25% of its former value remains unity because the control rod provides a reduced number of neutrons. The number of neutrons provided by the control rod completes the deficiency of neutrons due to a reduction in power output.
Therefore, the multiplication factor for power output to 25% of its former value remains unity.
The uranium ore mined today contains only 0.72% of fissionable , too little to make reactor fuel for thermal-neutron fission. For this reason, the mined ore must be enriched with . Both role="math" localid="1661753958684" and are radioactive. How far back in time would natural uranium ore have been a practical reactor fuel, with a ratio of 3.0%?
Roughly 0.0150% of the mass of ordinary water is due to “heavy water,” in which one of the two hydrogens in an molecule is replaced with deuterium, . How much average fusion power could be obtained if we “burned” all the in 1.00 litre of water in 1.00 day by somehow causing the deuterium to fuse via the reaction ?
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