Log In Start studying!

Select your language

Suggested languages for you:
Answers without the blur. Sign up and see all textbooks for free! Illustration

Q46P

Expert-verified
Fundamentals Of Physics
Found in: Page 1333

Answers without the blur.

Just sign up for free and you're in.

Illustration

Short Answer

In certain stars the carbon cycle is more effective than the proton–proton cycle in generating energy.This carbon cycle is

C12+H113N+γ, Q1=1.95 MeV,N1313C+e++v, Q2=1.19,C13+H114N+γ, Q3=7.55,C14+H115O+γ, Q4=7.30,15O 15N+e++v, Q5=1.73,C15+H112C+4He, Q6=4.97

(a) Show that this cycle is exactly equivalent in its overall effects to the proton–proton cycle of Fig. 43-11. (b) Verify that the two cycles, as expected, have the same Q value.

(a) The carbon cycle is exactly equivalent to proton-proton cycle.

(b) It is verified that the two cycles have the same Q value.

See the step by step solution

Step by Step Solution

Step 1: Describe the expression for energy

The expression for energy is given by,

Q=-mc2

Here, is the energy release in a reaction, m is the mass difference between the parent nuclei and the daughter nuclei, and c is the velocity of light.

Step 2: Show that carbon-carbon cycle is exactly equivalent to the proton–proton cycle(a)

If can be carefully observed thatin the carbon-carbon cycle, the products are two positrons 2e+ , two neutrinos 2v , and one helium nucleus H4e .

The same products are also obtained in the proton-proton cycle.

Therefore, the carbon cycle is exactly equivalent to proton-proton cycle.

Step 3: Verify that the two cycles have the same Q value(b)

The value of the energy is the sum of the Q values of the carbon cycle.

Qc=n=16Qn=Q1+Q2+Q3+Q4+Q5+Q6=1.95Mev+1.19Mev+7.55Mev+7.30Mev+1/73Mev+4.97Mev=24.7 Mev

The Q value is same for both cycles.

Therefore, it is verified that the two cycles have the same Q value.

Most popular questions for Physics Textbooks

Icon

Want to see more solutions like these?

Sign up for free to discover our expert answers
Get Started - It’s free

Recommended explanations on Physics Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.