Book edition 10th Edition

Author(s) David Halliday

Pages 1328 pages

ISBN 9781118230718

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Short Answer

The fission properties of the plutonium isotope ${}^{239}{Pu}$ are very similar to those of ${}^{235}U$ . The average energy released per fission is 180 MeV. How much energy, in MeV, is released if all the atoms in 1.0 kg of pure ${}^{239}{Pu}$ undergo fission?

The released energy is $4.534 \times 10^{26} MeV$ .

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1: Given data

The mass of the plutonium isotope,m = 1 kg

The average energy released per fission,Q = 180 MeV

The molar mass of plutonium, M = 239

Step 2: Determine the formulas to calculate the released energy.

The equation to calculate the number of the atoms in the sample is given as follows.

$N = \frac{m N_{A}}{M}$ ...(i)

Here, $N_{A}$ is the Avogadro number $(6.022 \times 10^{23} {mol}^{- 1})$ and M is the molar number.

The expression to calculate the released energy is given as follows.

$E = NQ$ ...(ii)

Step 3: Calculate the released energy in the fission.

Calculate the number of the atoms.

Substitute $239 f o r M, 1 k g f o r m a n d 6.022 \times 10^{23 m o l^{- 1}} f o r N_{A}$ into equation (i).

$N = \frac{1000 \times 6.022 \times 10^{23}}{239} N = \frac{6022 \times 10^{23}}{239} N = 25.19 \times 10^{23} N = 2.519 \times 10^{24}$

Calculate the released energy.

Substitute $2.519 \times 10^{24} f o r N a n d 180 M e V f o r Q$ into equation (ii).

$E = 2.519 \times 10^{24} \times 180 E = 453.42 \times 10^{24} MeV E = 4.534 \times 10^{26} MeV$

Hence the released energy is $4.534 \times 10^{26} MeV$ .

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Fundamentals Of Physics

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Short Answer

The fission properties of the plutonium isotope ${}^{239}{Pu}$ are very similar to those of ${}^{235}U$ . The average energy released per fission is 180 MeV. How much energy, in MeV, is released if all the atoms in 1.0 kg of pure ${}^{239}{Pu}$ undergo fission?

Step by Step Solution

Step 1: Given data

Step 2: Determine the formulas to calculate the released energy.

Step 3: Calculate the released energy in the fission.

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The fission properties of the plutonium isotope Pu239 are very similar to those of U235. The average energy released per fission is 180 MeV. How much energy, in MeV, is released if all the atoms in 1.0 kg of pure Pu239 undergo fission?

Step by Step Solution

Step 1: Given data

Step 2: Determine the formulas to calculate the released energy.

Step 3: Calculate the released energy in the fission.

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The fission properties of the plutonium isotope ${}^{239}{Pu}$ are very similar to those of ${}^{235}U$ . The average energy released per fission is 180 MeV. How much energy, in MeV, is released if all the atoms in 1.0 kg of pure ${}^{239}{Pu}$ undergo fission?