In the deuteron–triton fusion reaction of Eq. 43-15, what is the kinetic energy of (a) the alpha particle and (b) the neutron? Neglect the relatively small kinetic energies of the two combining particles.
Assume that the initial velocities is negligible, from the conservation of the energy,
Here, Q is total energy, is kinetic energy of alpha particle, and is kinetic energy of neutron.
From the conservation of the momentum,
Divide both sides of the above equation by .
It is known that .
From the equation,
From equation (1),
The mass of the alpha particle is and the mass of the neutron is , where .
Substitute all the known values in equation (2).
Therefore, the kinetic energy of alpha particle is 3.541MeV.
Substitute all the known values in equation (1).
Therefore, the kinetic energy of neutron is 14.05 MeV.
The neutron generation time (see Problem 19) of a particular reactor is 1.3 ms .The reactor is generating energy at the rate of 1200.0 MW.To perform certain maintenance checks, the power level must temporarily be reduced to 350.00 MW. It is desired that the transition to the reduced power level take 2.6000 s. To what (constant) value should the multiplication factor be set to effect the transition in the desired time?
Question: Consider the fission of by fast neutrons. In one fission event, no neutrons are emitted and the final stable end products, after the beta decay of the primary fission fragments, are . (a) What is the total of the beta-decay events in the two beta-decay chains? (b) Calculate for this fission process. The relevant atomic and particle masses are
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