Book edition 10th Edition

Author(s) David Halliday

Pages 1328 pages

ISBN 9781118230718

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Short Answer

(a) Calculate the disintegration energy Q for the fission of the molybdenum isotope ${}^{98}M o$ into two equal parts. The masses you will need are 97.90541u for ${}^{98}M o$ and 48.95002u for ${}^{49}S c$ . (b) If Q turns out to be positive, discuss why this process does not occur spontaneously.

(a) The disintegrated energy is 5 MeV.

(b) Due to the energy barrier the process is not spontaneously.

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1: Given data

The mass of ${}^{98}M o, m_{M o} = 97.90541 u$ ,

The mass of ${}^{49}S c, m_{S C} = 48.95002 u$ ,

Step 2: Determine the formula to calculate the disintegrated energy

The expression to calculate the disintegrated energy is given as follows.

$Q = - ∆ m c^{2} Q = (m_{M o} - 2 m_{S C}) c^{2}$ ...(i)

Step 3: (a) Calculate the value of disintegrated energy.

Consider the fission reaction as given follow.

${}^{98}M o \to {}^{49}S c + {}^{49}S c$

Calculate the disintegrated energy.

Substitute 97.90514u for $m_{M o}$ ,48.95002u for $m_{S c}$ and 931.5 MeV/u for $c^{2}$ into equation (i).

$Q = (97.90541 u - 2 \times 48.95002 u) 931.5 MeV / u Q = 0.00537 \times 931.5 MeV Q = 5 MeV$

Hence the disintegrated energy is 5 MeV.

Step 4: (b) Determine the why the process does not occur spontaneously.

From the part (a), the disintegrated energy is +5Mev. The nucleus must overcome the barrier of the energy which is larger than the +5MeV. Therefore, the positive sign of disintegrated energy does not indicate that the process is spontaneously. Therefore, due to the energy barrier the process is not spontaneously.

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Fundamentals Of Physics

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Short Answer

(a) Calculate the disintegration energy Q for the fission of the molybdenum isotope ${}^{98}M o$ into two equal parts. The masses you will need are 97.90541u for ${}^{98}M o$ and 48.95002u for ${}^{49}S c$ . (b) If Q turns out to be positive, discuss why this process does not occur spontaneously.

Step by Step Solution

Step 1: Given data

Step 2: Determine the formula to calculate the disintegrated energy

Step 3: (a) Calculate the value of disintegrated energy.

Step 4: (b) Determine the why the process does not occur spontaneously.

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Fundamentals Of Physics

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Short Answer

(a) Calculate the disintegration energy Q for the fission of the molybdenum isotope M98o into two equal parts. The masses you will need are 97.90541u for M98o and 48.95002u for S49c. (b) If Q turns out to be positive, discuss why this process does not occur spontaneously.

Step by Step Solution

Step 1: Given data

Step 2: Determine the formula to calculate the disintegrated energy

Step 3: (a) Calculate the value of disintegrated energy.

Step 4: (b) Determine the why the process does not occur spontaneously.

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(a) Calculate the disintegration energy Q for the fission of the molybdenum isotope ${}^{98}M o$ into two equal parts. The masses you will need are 97.90541u for ${}^{98}M o$ and 48.95002u for ${}^{49}S c$ . (b) If Q turns out to be positive, discuss why this process does not occur spontaneously.