The coefficient of static friction between Teflon and scrambled eggs is about .What is the smallest angle from the horizontalthat will cause the eggs to slide across the bottom of a Teflon-coated skillet?
The smallest angle from the horizontalthat will cause the eggs to slide across the bottom of a Teflon-coated skillet is
Coefficient of static friction,
The problem is based on Newton’s second law of motion which states that the rate of change of momentum of a body is equal in both magnitude and direction of the force acting on it. Thus, using the free body diagram, The smallest angle from the horizontal that will cause the eggs to slide across the bottom of a Teflon-coated skillet can be found.
where, F is the net force, m is mass and a is an acceleration.
Free body Diagram of egg over the skillet:
By using Newton’s 2nd law along vertical direction (along y),
Since, block is not moving upward,
Relation between Static frictional force and Normal force is,
Now, applying Newton’s 2nd along the x direction,
Since, block is not moving,
By using equation (i) in the above equation,
Hence, the smallest angle from the horizontalthat will cause the eggs to slide across the bottom of a Teflon-coated skillet is
In Fig. 6-37, a slab of mass rests on a frictionless floor, and a block of mas rests on top of the slab. Between block and slab, the coefficient of static friction is , and the coefficient of kinetic friction is . A horizontal force of magnitude begins to pull directly on the block, as shown. In unit-vector notation, what are the resulting accelerations of (a) the block and (b) the slab?
In Fig. 6-24, a force acts on a block weighing .The block is initially at rest on a plane inclined at angle to the horizontal. The positive direction of the x axis is up the plane. Between block and plane, the coefficient of static friction is and the coefficient of kinetic friction is . In unit-vector notation, what is the frictional force on the block from the plane when is (a) , (b) , and (c) ?
A 100 N force, directed at an angle above a horizontal floor, is applied to a 25.0 kg chair sitting on the floor. If , what are (a) the horizontal component of the applied force and (b) the magnitudeN of the normal force of the floor on the chair? If , what are (c) and (d) ? If , what are (e) and (f) ? Now assume that the coefficient of static friction between chair and floor is 0.420 . Does the chair slide or remain at rest if is (g) , (h) , and (i) ?
In Fig. 6-39, a car is driven at constant speed over a circular hill and then into a circular valley with the same radius. At the top of the hill, the normal force on the driver from the car seat is 0. The driver’s mass is .What is the magnitude of the normal force on the driver from the seat when the car passes through the bottom of the valley?
94% of StudySmarter users get better grades.Sign up for free