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Q36P
Expert-verifiedThe terminal speed of a sky diver is in the spread-eagle position and in the nosedive position. Assuming that the diver’s drag coefficient C does not change from one position to the other, find the ratio of the effective cross-sectional area A in the slower position to that in the faster position.
The ratio of the effective cross-sectional area A in the slower position to that in the faster position is
which illustrates the inverse proportionality between the area and the speed-squared
thus
This problem is based on the drag force which is a type of friction. This is the force acting opposite to the relative motion of an object moving with respect to the surrounding medium. Using the concept of the drag force and terminal speed the ratio of the effective cross-sectional area A in the slower position to that in the faster position.
Formula:
The terminal speed is given by
Where C is the drag coefficient, is the fluid density, A is the effective cross-sectional area, and is the gravitational force.
solve for the area
which illustrates the inverse proportionality between the area and the speed-squared
When a ratio of areas has been setup of the slower case to the faster case,
Hence, the ratio of the effective cross-sectional area A in the slower position to that in the faster position is
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