A particle of charge is placed at one corner of a Gaussian cube. What multiple of gives the flux through (a) each cube face forming that corner and (b) each of the other cubes faces?
The total flux through any surface that completely surrounds the point charge is
Using the concept of Gauss law and the planar symmetry, we can get the net flux through each cube face by considering the concept of total flux through the cube.
If we stack identical cubes side by side and directly on top of each other, we will find that eight cubes meet at any corner.
Thus, one-eighth of the field lines emanating from the point charge pass through a cube with a corner at the charge, and the total flux through the surface of such a cube is .
Now the field lines are radial, so at each of the three cube faces that meet at the charge, the lines are parallel to the face and the flux through the face is zero.
The fluxes through each of the other three faces are the same, so the flux through each of them is one-third of the total.
That is, the flux through each of these faces is given as:
Thus, the multiple factors are 1/24 or 0.0417.
A Gaussian surface in the form of a hemisphere of radius lies in a uniform electric field of magnitude . The surface encloses no net charge. At the (flat) base of the surface, the field is perpendicular to the surface and directed into the surface. What is the flux through
(a) the base and
(b) the curved portion of the surface?
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