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Fundamentals Of Physics
Found in: Page 383

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Short Answer

A satellite orbits a planet of unknown mass in a circle of radius 2.0×107 m. The magnitude of the gravitational force on the satellite from the planet is F=80N.

(a) What is the kinetic energy of the satellite in this orbit?

(b) What would F be if the orbit radius were increased to 3.0×107 m ?

  1. Kinetic energy of the satellite K= 8.0 × 108J
  2. Gravitational force when the orbit radius is increased to 3×107 m  is (F2) = 35.5N
See the step by step solution

Step by Step Solution

Step 1: Listing the given quantities

r1= 2×107 m

F1 = 80N

r2 = 3× 107 m

Step 2: Understanding the concept of gravitational force and kinetic energy

Using the given gravitational force and kinetic energy formula, we can find the kinetic energy of the satellite ( Ks ). Using F1r2 , we can find gravitational force F2 when the radius is increased to 3×107 m

Formula:

K= GMm2(r)

F= GMmr2

Step 3: (a) Calculation of kinetic energy of satellite  

K= GMm2(r1)

F1= GMmr12

F1×r1 = GMmr1

Using this in kinetic energy equation (1),

K= 12 F1×r1 = 12 80 N× 2× 107 m= 8.0 × 108J

Step 4: (b) Calculation of Gravitational force when the orbit radius is increased 

F11r12F21r22F1F2=r22r12F1F2=(2×107 m)2(3×107 m)2F1F2=49

Using the given value of F1

F2 = 4 ×80 N9 = 35.5 N

Gravitational force when the orbit radius is increased to 3×107 m isF2 = 35.5 N

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