Book edition 10th Edition

Author(s) David Halliday

Pages 1328 pages

ISBN 9781118230718

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Short Answer

Find the slit separation of a double-slit arrangement that will produce interference fringes $0.018 rad$ apart on a distant screen when the light has wavelength $λ = 589 nm$ .

Thus, the wavelength of visible light is $33 μ m$ .

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1: According to the question.

In the case of a distant screen the angle $θ$ is close to zero so $s i n θ \approx θ$

Thus, solve further gives:

$Δ θ \approx Δ s i n θ = Δ (\frac{m λ}{d}) = \frac{λ}{d} Δ m Δ θ = \frac{λ}{d}$

Here, $λ$ is wavelength of light in air/vacuum.

Step 2: The wavelength of visible light.

Use the above formula as follows:

$d = \frac{λ}{Δ θ} = \frac{589 \times 10^{- 9} m}{0.018 r a d} = 3.3 \times 10^{- 5} m = 33 μ m$

Hence, the wavelength of visible light is $33 μ m$ .

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Fundamentals Of Physics

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Short Answer

Find the slit separation of a double-slit arrangement that will produce interference fringes $0.018 rad$ apart on a distant screen when the light has wavelength $λ = 589 nm$ .

Step by Step Solution

Step 1: According to the question.

Step 2: The wavelength of visible light.

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Fundamentals Of Physics

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Short Answer

Find the slit separation of a double-slit arrangement that will produce interference fringes 0.018 radapart on a distant screen when the light has wavelength λ=589 nm.

Step by Step Solution

Step 1: According to the question.

Step 2: The wavelength of visible light.

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Find the slit separation of a double-slit arrangement that will produce interference fringes $0.018 rad$ apart on a distant screen when the light has wavelength $λ = 589 nm$ .