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Expert-verified Found in: Page 863 ### Fundamentals Of Physics

Book edition 10th Edition
Author(s) David Halliday
Pages 1328 pages
ISBN 9781118230718 # A long wire carrying 100A is perpendicular to the magnetic field lines of a uniform magnetic field of magnitude 5.0 mT. At what distance from the wire is the net magnetic field equal to zero?

Point on the line parallel to the wire at a distance $r=4.0×{10}^{-3}\text{m}$

See the step by step solution

## Step 1: Given

${B}_{ext}=5.0×{10}^{-3}\text{\hspace{0.17em}T}$, the field lines are perpendicular to the wire i=100A.

## Step 2: Understanding the concept

We can use the equation for the field produced by the long current-carrying wire at a point away from the wire. The distance should be such that the field produced by the wire is exactly the same as the given field.

Formula:

Magnetic field due to a long straight wire at distance r from the wire carrying current i

${B}_{r}=\frac{{\mu }_{0}i}{2\pi r}$

## Step 3: Calculate distance from the wire where the net magnetic field is zero

Since the long wire is kept in an external magnetic field, the field due to wire (Bw) and external magnetic field (Bext) will cancel out when their magnitudes are the same, and the direction is opposite. So, the set points which will satisfy this condition lie on the line parallel to the wire at distance r.

$\begin{array}{c}{B}_{r}=\frac{{\mu }_{0}i}{2\pi r}={B}_{ext}\\ r=\frac{{\mu }_{0}i}{2\pi {B}_{ext}}\\ r=\frac{1.26×{10}^{-6}×100}{2×\pi ×5.0×{10}^{-3}}\\ r=4.0×{10}^{-3}\text{\hspace{0.17em}m}\end{array}$

Hence, the Point on the line parallel to the wire at a distance $r=4.0×{10}^{-3}\text{m}$

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