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Expert-verifiedA certain particle is sent into a uniform magnetic field, with the particle’s velocity vector perpendicular to the direction of the field. Figure 28-37 gives the period T of the particle’s motion versus the inverseof the field magnitude B. The vertical axis scale is set by , and the horizontal axis scale is set by
what is the ratio m/q of the particle’s mass to the magnitude of its charge?
The ratio m/q of the particle’s mass to the magnitude of its charge is .
Y axis scale is .
X axis scale is
Figure 28-37 is the graph of
Use the concept of the period of the particle in a uniform magnetic field. Use the equation of period related to mass, charge, and magnetic field. Find the slope of the graph and plug it intothe equation. Rearranging the equation for , find this ratio.
Formulae are as follows:
Where T is the time period, B is the magnetic field, m is mass, and q is the charge ofthe particle.
Using the equation,
Rearranging it for ,
We have the value of ,
From the graph, find the slope
For the y-axis, one unit is , and for the x-axis, one unit is
Using this value in the above equation of ,
Hence, the ratio m/q of the particle’s mass to the magnitude of its charge is .
Therefore, by using the concept of the period of the particle in a uniform magnetic field and equations the ratio can be determined.
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