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Fundamentals Of Physics
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Short Answer

Suppose that a parallel-plate capacitor has circular plates with a radius R=30 mm and, a plate separation of 5.00 mm. Suppose also that a sinusoidal potential difference with a maximum value of 150 V and, a frequency of 60 Hz is applied across the plates; that is,

V=(150 V)sin[2π(60 Hz)t]

(a) Find BmaxR, the maximum value of the induced magnetic field that occurs at r=R.

(b) Plot Bmaxr for 0<r<10 cm.

  1. The maximum value of the induced magnetic field that occurs at r=R is B=1.9×10-12.
  2. The plot is given in the calculation section.
See the step by step solution

Step by Step Solution

Step 1: Given

The radius of plates, R=30 mm=0.03 m

Plate separation, d=0.005 m

Maximum potential difference, V=150 V

Frequency, f=60 Hz

V=150 sin 2π60 Hzt

Step 2: Determining the concept

By using the Maxwell equation, finding the magnetic field for the maximum potential, and plotting the graph maximum B vs r Maxwell's equations represent one of the most elegant and concise ways to state the fundamentals of electricity and magnetism.

Maxwell’s law of Induction-

.B.dA=μ0E0 AdEdt

The electric field is given as-

E=Vd

Where, B is the magnetic field, is the area enclosed by the Amperian loop, E is the electric field, t is the time, V is the potential difference and, d is the distance.

Step 3: (a) Determining the maximum value of the induced magnetic field that occurs at r=R

The electric field is given as-

E=Vd

The magnetic field induced by the changing electric field is given by the relation,

localid="1663162361810" style="max-width: none; vertical-align: -15px;" B.dA=μ0E0 AdEdt

Where, localid="1663162418635" A is the area enclosed by the Amperian loop, which is, localid="1663162390281" A=πd2 .

So that, for r<R,

B2πr=μ0E0πr2dEdt B=μ0E0r2dEdt

But,

E=Vd

So,

B=μ0E0r2ddVdt B=μ0E0r2dddtVmaxsinωtB=μ0E0r2dVmaxωcosωt

For the maximum value of potential Vmax=150 V,

B=μ0E0r2dVmaxω

The r=R=0.03 m

localid="1663161555184" B=4π×10-7 H/m8.85×10-12 F/m×0.03 m2×0.005 m×150×2π×60 HzB=1.9×10-12 T

Therefore, the maximum value of the induced magnetic field that occurs at r=R is B=1.9×10-12 T.

Step 4: (b) Determining the required plot

The maximum value of B, the magnetic field is induced by the changing electric field so that,

Bmax=μ0E0R22rdEdt maxBmax=μ0E0R22rddVdt maxBmax=μ0E0R22rdVmaxωcosωt maxBmax=μ0E0R22rdVmaxω max

So, all values are constant except r.

B is dependent on the value of r, so plot the graph B vs r.

Bmax=4π×10-7 H/m8.85×10-12 F/m×0.03 m22×0.005 m×r×150×2π×60 Hz=5.7×10-14×1r

Here, r varies from 0 to 0.1.

Hence, plotted the graph Bmax vs r, for varying from 0 to 0.1.

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