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Fundamentals Of Physics
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Short Answer

Calculate the probability that the electron in the hydrogen atom, in its ground state, will be found between spherical shells whose radii are a and 2a , where a is the Bohr radius?

The required probability is P=0.439.

See the step by step solution

Step by Step Solution

Step 1: Identification of the given data:

The given data is listed below.

  • Radii of the spherical shells are given as a and 2a .

Step 2: Formula for finding the probability of electron:

The ground state wave function of hydrogen atom is given by,

ψ100(r,θ,ϕ)=1π(1a)32e-ra

Here, the Bohr radius is a=5.292×10-11m.

Step 3: Determine the probability of the electron in the hydrogen atom in its ground state:

The probability of finding the electron found between spherical shells is,

P=a2a0π02πψ100r,θ,ϕ2r2drsinθdθdϕ =a2a1π1a32e-ra2r2dr0π =1π1a3a2ae-ra2r2dr×-cosθ0πθ02π =1π1a3-14ae-2raa2+2ar+2r2a2a×-cosπ+cos02π-0

P=1π1a3-a4e-22aaa2+2a2a+22a2-e-2aaa2+2a2+2a2×--1+12π =1π1a3-a4e-413a2-e-25a2×4π =41a3-a40.018313a2-0.13535a2P=4-140.018313-0.13535 =-4140.2379-0.6765 =0.439

Hence, the probability of the electron in the hydrogen atom in its ground state is 0.439.

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