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Fundamentals Of Physics
Found in: Page 33

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Short Answer

An electron with an initial velocityV0=1.50×105 m/senters a region of length L=1.00cm where it is electrically accelerated. It emerges withv=5.70×106m/s. What is its acceleration, assumed constant?

The acceleration of electron to be assumed constant is 1.62×1015m/s2 .

See the step by step solution

Step by Step Solution

Step 1: Given Data

Initial velocity, v0=1.50×105m/s

Final velocity, v=5.70×105m/s

Distance travelled, x=1.00 cm

Step 2: Understanding the concept of acceleration

Acceleration can be found by using the given data in the kinematic equation which involves initial velocity, final velocity, acceleration, and displacement terms.

The formula to find acceleration can be obtained with the help of final as well as initial velocity.

v2=v02+2axHere, v is the final velocity,v0 is the initial velocity,a is the acceleration and x is the distance travelled.

Step 3: Determination of the acceleration.

Convert 1.00 cm into i.e. in S.I. units.

1cm=1cm100cm×1m =0.01mRearrange the equation (i) to calculate the acceleration as,a=v2-v022xSubstitute the values in the above expression.a=5.7×106m/s2-1.5×105m/s22×0.01m =1.62×1015 m/s2Therefore, the acceleration of the electron to be assumed constant is 1.62×1015 m/s2 .

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