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Fundamentals Of Physics
Found in: Page 34

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Short Answer

A muon (an elementary particle) enters a region with a speed of 5.00×106 m/s and then is slowed down at the rate of 1.25×1014 m/s2. (a) How far does the muon take to stop? (b) Graph x vs t and v vs t for the muon.

(a) The distance muon takes to stop is 0.100 m .

(b) The graphs of x vs t and v vs tare plotted for the muon.

See the step by step solution

Step by Step Solution

Step 1: Given Data

Initial speed of muon is, vi=5.00×106 m/s

Acceleration of the muon is, a=-1.25×1014 m/s2

Step 2: Understanding the kinematic equations of motion.

Kinematic equations of motion describe the relationship between displacement, velocity or acceleration of a particle. The graphs of displacement vs time and velocity vs timecan be plotted to analyze the motion of the particle.

The expression for the equation of motion is given as below,


Here, vf is the final velocity, vi is the initial velocity, a is the acceleration, and x is the distance.

Step3: (a) Determination of the distance required for muon to stop

Rearrange the equation (i) for x and substitute the values.

x=vf2-vi22a =02-5.00×10622×-1.25×1014 =0.100 m

Step 4: (b) Plotting the graph of x vs t and v vs t.

To plot graph of vs kinematic equationis used,


To plot graph of vs t kinematic equation is used,


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