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Fundamentals Of Physics
Found in: Page 1302

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Short Answer

Figure 42-18 is a plot of mass number A versus charge number Z. The location of a certain nucleus is represented by a dot. Which of the arrows extending from the dot would best represent the transition were the nucleus to undergo (a) a β decay and (b) a α decay?

  1. The arrows that would represent best for the nucleus that were to undergo β decay are d and h.
  2. The arrows that would represent best for the nucleus that were to undergo α decay is g.
See the step by step solution

Step by Step Solution

Step 1: Given data

Figure 42-18 shows the graph of a mass number versus atomic number.

Step 2: Understanding the concept of decay

There are two decays that the radionuclides mostly undergo. That is an alpha decay and beta decay.

Alpha decay is a type of radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and also a different nucleus with a mass number that is reduced by four and an atomic number that is reduced by two.

Beta decay is a radioactive decay in which a beta ray is emitted from an atomic nucleus. During beta decay, the proton in the nucleus is transformed into a neutron or vice versa. If a proton is converted to neutron, it is known as beta-plus decay. Similarly, if a neutron is converted to a proton, it is known as beta-minus decay.

Step 3: a) Calculation of the arrows that represent beta decay

The radioactive decay of a nuclide through beta decay process are of two types. They are beta-minus decay and beta-plus decay.

The beta-minus decay is decay with products as a different nuclide, an electron and an anti-neutrino. That can be given as: zAM z+1AN+e-+v¯

In the graph, the arrow may undergo beta-minus decay as their atomic number is increasing without any change to the mass number.

The beta-plus decay is decay with products as a different nuclide, a positron and a neutrino. That can be given as: zAM z-1AN+e-+v¯

In the graph, the arrow may undergo beta-minus decay as their atomic number is increasing without any change to the mass number.

Hence, the arrows that represent beta decay are d and h.

Step 4: b) Calculation of the arrows that represent alpha decay

An alpha decay of a zAM nuclide can be given as:

zAM z+1A-4N+ 24He (α-particle)

Here, the nuclides undergo a decrease in both the mass and atomic number simultaneously.

Hence, the arrow that best represent the alpha decay is g.

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