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Found in: Page 1307

### Fundamentals Of Physics

Book edition 10th Edition
Author(s) David Halliday
Pages 1328 pages
ISBN 9781118230718

# Make a nuclidic chart similar to Fig. 42-6 for the 25 nuclides ${}^{\mathbf{118}\mathbf{-}\mathbf{122}}{\mathbit{T}}{\mathbit{e}}$, ${}^{\mathbf{117}\mathbf{-}\mathbf{121}}{\mathbit{S}}{\mathbit{b}}$, ${}^{\mathbf{116}\mathbf{-}\mathbf{120}}{\mathbit{S}}{\mathbit{n}}$, ${}^{\mathbf{115}\mathbf{-}\mathbf{19}}{\mathbf{ln}}$, and ${}^{\mathbf{114}\mathbf{-}\mathbf{118}}{\mathbit{C}}{\mathbit{d}}$. Draw in and label (a) all isobaric (constant A) lines and (b) all lines of constant neutron excess, defined as N - Z.

1. A nuclidic chart for all the 25 nuclides is drawn by labeling all the isobaric lines.
2. A nuclidic chart for all the 25 nuclides is drawn by labeling all the lines of constant neutron excess defined as N - Z.
See the step by step solution

## Step 1: Given data

All the given 25 nuclides are: ${}^{118-122}Te,{}^{117-121}Sb,{}^{116-120}Sn,{}^{115-119}\mathrm{ln},{}^{114-118}Cd$

## Step 2: Understanding the concept of nuclidic chart

A nuclidic chart is a two-dimensional graph of isotopes of the elements, in which one axis represents the number of neutrons and the other represents the number of protons in the atomic nucleus. Each box represents a particular nuclide and is color-coded according to its predominant decay mode.

## Step 3: a) Calculation for the nuclide chart of isobaric lines

Although we haven’t drawn the requested lines in the following table, we can indicate their slopes: lines of constant A would have $-{45}^{0}$ slopes passing from the bottom right corner Cd-118 to the left top most corner to Te-118. The first column corresponds to N = 66, and the bottom row to Z = 48. The last column corresponds to N = 70, and the top row to Z = 52.

The nuclide chart is shown below:

## Step 4: b) Calculation for the nuclide chart of constant N-Z lines

Although we haven’t drawn the requested lines in the above table, we can indicate their slopes: lines of constant N - Z would have $45°$. As an example of the latter, the N - Z = 20 line (which is one of “eighteen-neutron excess”) would pass through Cd-114 at the lower left corner up through Te-122 at the upper right corner.