Find the disintegration energy Q for the decay of by Kelectron capture (see Problem 54). The needed data are and .
The disintegration energy for the decay of vanadium atom is 600 keV .
The mass of the vanadium atom is
The mass of the Titanium atom is
The energy for K electron capture is
The disintegration energy for an atom is the energy necessary for breaking the nucleus of the atom.
The disintegration energy for the decay of vanadium atom is given as:
Here, is the speed of light.
Substitute all the values in the above equation (1), and we get.
Therefore, the disintegration energy for the decay of vanadium atom is 100 keV.
The magic nucleon numbers for nuclei are given in Module 42-8 as 2, 8, 20, 28, 50, 82, and 126. Are nuclides magic (that is, especially stable) when (a) only the mass number A, (b) only the atomic number Z, (c) only the neutron number N, or (d) either Z or N (or both) is equal to one of these numbers? Pick all correct phrases.
94% of StudySmarter users get better grades.Sign up for free