Book edition 10th Edition

Author(s) David Halliday

Pages 1328 pages

ISBN 9781118230718

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Short Answer

Find the disintegration energy Q for the decay of $^{49} V$ by Kelectron capture (see Problem 54). The needed data are $m_{v} = 48.94852 u, m_{n} = 48.94787 u$ and .

The disintegration energy for the decay of vanadium atom is 600 keV .

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1: Identification of given data

The mass of the vanadium atom is $m_{v} = 48.94852 u$

The mass of the Titanium atom is $m_{Ti} = 48.94787 u$

The energy for K electron capture is $E_{k} = 5.47 keV$

Step 2: Concept Introduction

The disintegration energy for an atom is the energy necessary for breaking the nucleus of the atom.

The disintegration energy for the decay of vanadium atom is given as:

$E = (m_{v} - m_{Ti}) c^{2} - E_{k}$ …………………….(1)

Here, is the speed of light.

Step 3: Determination of disintegration energy for the decay of vanadium atom

Substitute all the values in the above equation (1), and we get.

$E = (48.94852 u - 48.94787 u) c^{2} - 5.47 keV = (0.00065 u) (c^{2}) ((\frac{1}{c^{2}}) (\frac{931.5 \times 10^{3} keV}{u})) - 5.47 keV = 600 keV$

Therefore, the disintegration energy for the decay of vanadium atom is 100 keV.

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Fundamentals Of Physics

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Short Answer

Find the disintegration energy Q for the decay of $^{49} V$ by Kelectron capture (see Problem 54). The needed data are $m_{v} = 48.94852 u, m_{n} = 48.94787 u$ and .

Step by Step Solution

Step 1: Identification of given data

Step 2: Concept Introduction

Step 3: Determination of disintegration energy for the decay of vanadium atom

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Fundamentals Of Physics

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Short Answer

Find the disintegration energy Q for the decay of 49Vby Kelectron capture (see Problem 54). The needed data are mv=48.94852 u, mn=48.94787u and .

Step by Step Solution

Step 1: Identification of given data

Step 2: Concept Introduction

Step 3: Determination of disintegration energy for the decay of vanadium atom

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Find the disintegration energy Q for the decay of $^{49} V$ by Kelectron capture (see Problem 54). The needed data are $m_{v} = 48.94852 u, m_{n} = 48.94787 u$ and .