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Found in: Page 438

### Fundamentals Of Physics

Book edition 10th Edition
Author(s) David Halliday
Pages 1328 pages
ISBN 9781118230718

# Question: The angle of the pendulum in Figure is given by . If at t = 0 , and , what is the phase constant , what is the maximum angle ? (Hint: Don’t confuse the rate at which changes with the of the SHM.)

1. The phase constant is 0.845 rad
2. The maximum angle is 0.0602 rad

See the step by step solution

## Step 1: Identification of given data

1. The angle of the pendulum is
2. At , and

## Step 2: Understanding the concept

The oscillations of the simple pendulum can be defined by the equation of simple harmonic motion. The simple harmonic motion is the motion in which the acceleration of the oscillating object is directly proportional to the displacement. The force caused by the acceleration is called restoring force. This restoring force is always directed towards the mean position.

Compare the given equation with the equation of displacement of the particle in simple harmonic motion.

Formulae:

## Step 3: (a) Determining the phase constant

The phase constant :

The expression for the displacement of the particle in simple harmonic motion is

Here, x (t) is the displacement, xm is amplitude, angular velocity, t is time, is phase difference.

For angular displacement, replace x by , then

…(i)

The expression for velocity of the particle in simple harmonic motion is

For angular motion, replace x by , then

…(ii)

Divide equation (ii) by equation (i)

Therefore, the phase constant is 0.845 rad .

## Step 4: (b) Determining the maximum angle

For t =0, equation (i) becomes as

The maximum angle is 0.0602 rad