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Fundamentals Of Physics
Found in: Page 1181

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Short Answer

The following nonrelativistic particles all have the same kinetic energy. Rank them in order of their de Broglie wavelengths, greatest first: electron, alpha particle, neutron.

The rank is electron, neutron, alpha particle.

See the step by step solution

Step by Step Solution

Step 1: Describe the de Broglie wavelength

The de Broglie wavelength is given by,

λ=hmv

Here, h is the plank’s constant, m is the mass and v is the velocity.

Step 2: Rank the de Broglie wavelengths for electron, alpha particle, and neutron

From the de Broglie wavelength, it can be observed that the mass of the particle is inversely proportional to the wavelength.

It is known that the mass of the neutron is mn=1.67×10-27 kg , the mass of alpha particle is mα=6.664×10-27 kg and the mass of the electron is me=9.11×10-31 kg. Clearly, me<mn<mα . So, rank of de Broglie wavelength is λe>λn>λα .

Therefore, the rank is electron, neutron, alpha particle.

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