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Q103P

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Found in: Page 211

### Fundamentals Of Physics

Book edition 10th Edition
Author(s) David Halliday
Pages 1328 pages
ISBN 9781118230718

# A sprinter who weighs 670 N runs the first 7.0 m of a race in 1.6 s, starting from rest and accelerating uniformly. What are the sprinter’s Speed and Kinetic energy at the end of the 1.6 s ? What average power does the sprinter generate during the 1.6 s interval?

1. The speed of the sprinter is 8.8 m/s .
2. Sprinter’s kinetic energy is 2.6 kJ .
3. Average power is 1.6 kW .
See the step by step solution

## Step 1: Given data:

Distance, S = 7.0 m

Time t = 1.6 s

Force, F = 670 N

Initial velocity, ${v}_{0}=0$

## Step 2: To understand the concept:

Use the four equations of motion to solve such problems. Use the first and second equations of motion to get the value for acceleration and velocity accordingly.

The average power of the sprinter generated during the given time interval can be found by dividing the kinetic energy produced by the sprinter.

Formulae:

Equations of motion,

$S=vt+\frac{1}{2}a{t}^{2}\phantom{\rule{0ex}{0ex}}{v}_{f}={v}_{0}+at$

Here, S is the displacement, v is the average velocity, ${v}_{f}$ is the final velocity, ${v}_{0}$ is the initial velocity, a is the acceleration, and t is time.

Kinetic energy is define by,

$KE=\frac{1}{2}m{v}^{2}$

Here, m is the mass.

Average power is given by,

${P}_{avg}=\frac{KE}{t}$

## Step 3: (a) Calculate the sprinters speed:

From the equation of motion, you have

$S={v}_{0}t+\frac{1}{2}a{t}^{2}\phantom{\rule{0ex}{0ex}}7.0\mathrm{m}=0+0.5×\mathrm{a}×{\left(1.6\mathrm{s}\right)}^{2}\phantom{\rule{0ex}{0ex}}\mathrm{a}=5.469\mathrm{m}/{\mathrm{s}}^{2}$

Using the second equation of motion,

$\mathrm{v}={\mathrm{v}}_{0}+\mathrm{at}\phantom{\rule{0ex}{0ex}}=0+5.469\mathrm{m}/{\mathrm{s}}^{2}×1.6\mathrm{s}\phantom{\rule{0ex}{0ex}}=8.8\mathrm{m}/\mathrm{s}$

Hence, the speed of the sprinter is 8.8 m/s .

## Step 4: (b) Calculate the kinetic energy at the end of the 1.6 s :

You know that kinetic energy is,

$KE=\frac{1}{2}m{v}^{2}$

But from Newton’s second law,

$\mathrm{m}=\mathrm{F}/\mathrm{g}\phantom{\rule{0ex}{0ex}}=\frac{670\mathrm{N}}{9.8\mathrm{m}/{\mathrm{s}}^{2}}\phantom{\rule{0ex}{0ex}}=68.36\mathrm{kg}$

Therefore, the kinetic energy will be,

$\mathrm{KE}=0.5×\left(68.36\mathrm{kg}\right)×{\left(8.8\mathrm{m}/\mathrm{s}\right)}^{2}\phantom{\rule{0ex}{0ex}}=2617.18\mathrm{J}\phantom{\rule{0ex}{0ex}}=2.6\mathrm{kJ}$

Hence, the sprinter’s kinetic energy is 2.6 kJ.

## Step 6: (c) Calculate the average power the sprinter generates during the 1.6s  interval:

Average power can be written as

${P}_{avg}=\frac{KE}{t}\phantom{\rule{0ex}{0ex}}=\frac{2617.18\mathrm{J}}{1.6s}\phantom{\rule{0ex}{0ex}}=1635.74\mathrm{W}\phantom{\rule{0ex}{0ex}}=1.6\mathrm{kW}$

Hence, the average power is 1.6 W.