• :00Days
  • :00Hours
  • :00Mins
  • 00Seconds
A new era for learning is coming soonSign up for free
Log In Start studying!

Select your language

Suggested languages for you:
Answers without the blur. Sign up and see all textbooks for free! Illustration


Fundamentals Of Physics
Found in: Page 202

Answers without the blur.

Just sign up for free and you're in.


Short Answer

What is the spring constant of a spring that stores 25 Jof elastic potential energy when compressed by 7.5 cm?

Spring constant is,k=8.9×103 N/m .

See the step by step solution

Step by Step Solution

Step 1: Given

Elastic potential energy U=25  J

Compressed lengthx =7.5 cm=7.5×102 m .

Step 2: To understand the concept 

The problem is based on the concept of elastic potential energy. It is energy stored as a result of applying a force to deform an elastic object. By using the concept of elastic potential energy, we can find the spring constant.



Step 3: Calculate the spring constant of the spring 

Elastic potential energy can be written as


Substitute all the value in the above equation.

k=2×25 J(7.5×102 m)2k=8.9×103 N/m

Hence the spring constant is, k=8.9×103 N/m.

Most popular questions for Physics Textbooks


Want to see more solutions like these?

Sign up for free to discover our expert answers
Get Started - It’s free

Recommended explanations on Physics Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.