Consider the neutrino whose symbol is . (a) Is it a quark, a
lepton, a meson, or a baryon? (b) Is it a particle or an antiparticle? (c) Is it a boson or a fermion? (d) Is it stable against spontaneous decay?
(a) It is a neutrino which is unchanged leptons therefore this is a lepton.
(b) neutrinos have a positive charge therefore it is an antiparticle.
(c) The antiparticle is a lepton that has a 1/2 spin therefore the particle is fermion.
(d) Yes, it is stable against spontaneous decay.
Properties of Leptons
Given neutrino is
Since it is a neutrino which is unchanged leptons therefore this is a lepton.
We know that leptons have an electric charge equal to -1e and uncharged leptons (neutrinos), one corresponding to each of the charged leptons. The antiparticles for the charged leptons have a positive charge.
We know If the spin is a one-half integer, then the particle is a fermion. If the spin is an integer, such as zero or one or two, then the particle is a boson.
Since the antiparticle is a lepton that has a 1/2 spin therefore the particle is a fermion.
Since it is a lepton which is a fundamental particle, and all the fundamental particles are light and stable they cannot interact by any strong force. So, it is stable against spontaneous decay.
Hence, yes, it is stable against spontaneous decay.
In the laboratory, one of the l;ines of sodium is emitted at a wavelength of 590.0 nm. In the light from a particular galaxy, however, this line is seen at a wavelength of 602.0 nm. Calculate the distance to the galaxy, assuming that Hubble’s law holds and that the Doppler shift of Eq 37-36 applies.
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