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Q22P

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Fundamentals Of Physics
Found in: Page 1364

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Short Answer

A 220 MeV particle decays: π+n. Calculate the total kinetic energy of the decay products.

The total kinetic energy of the decay energy is.338 Mev

See the step by step solution

Step by Step Solution

Step 1: Law of conservation of energy.

The law of conservation of energy is define as the energy can neither be created nor destroyed, only converted from one form of energy to another form.

Step 2: Calculate the total kinetic energy of the decay energy

The given reaction is written as:

π+n

Solve the total kinetic energy of the decay energy as follows:

Q=(BE)p~(BE)R=Δmc2+Qinitial=(mΛ0mpmπ)c2+Qinitial

Substitute the values from the standard data

Q=(1197.3139.6939.6+220)Mev=338 Mev

Thus, the total kinetic energy of the decay energy is.338 Mev

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