Americas
Europe
Q6Q
Expert-verifiedDoes the proposed decay conserve (a) electric charge, (b) spin angular momentum, and (c) strangeness? (d) If the original particle is stationary, is there enough energy to create the decay products?
(a) The electric charge is conserved.
(b) The spin angular momentum is conserved.
(c) The Strangeness is conserved.
(d) There is not enough energy to create the decay products.
The proposed decay is given as
Where, is lambda-zero
p is proton
is Kaon
From the property of particles, we can determine the total charge, angular momentum, and Strangeness of decay
Properties of Lambda, proton, and Kaon
Particle, symbol | Charge | spin | Strangeness |
Lambda, | 0 | 1/2 | -1 |
Proton, p | +1 | 1/2 | 0 |
Kaon, | -1 | 0 | -1 |
The proposed decay is given as
The charge on the is zero so the left side of the equation has a total charge of zero.
p has +1 charge and has -1 charge, so the total change on the left side of the equation is zero.
Since both, sides of the equation have the same charge, so the charge is conserved.
The proposed decay is given as
The has 1/2 spin, so the left side of the equation has 1/2 spin angular momentum
p has 1/2 spin and has 0 spin, so the total spin angular momentum on the right side of the equation is 1/2 .
Since both, sides of the equation have the same spin angular momentum, so the spin angular momentum is conserved.
The proposed decay is given as
The has a Strangeness number -1 , so the left side of the equation has -1 strangeness.
p has strangeness number 0 and has strangeness number -1 , so the total Strangeness on the right side of the equation is -1
Since both, sides of the equation have the same Strangeness, Therefore Strangeness is conserved.
The energy require for decay can be given as
Initial total mass-energy – final total mass-energy
The rest mass of lambda is,
The rest mass of a proton
The rest mass of Kaon
Since the rest mass of lambda particles is less than the total rest mass of the
Proton and Kaon.
Therefore, its rest energy is less than the energy of the proton, and Keon
The initial energy is less than the final energy of the particles therefore there is not enough energy to create the decay products.
94% of StudySmarter users get better grades.
Sign up for free