 Suggested languages for you:

Europe

Answers without the blur. Sign up and see all textbooks for free! Q101P

Expert-verified Found in: Page 294 ### Fundamentals Of Physics

Book edition 10th Edition
Author(s) David Halliday
Pages 1328 pages
ISBN 9781118230718 # In Fig${\mathbf{\text{10-61}}}$., four pulleys are connected by two belts. Pulley A (radius${\mathbf{\text{15\hspace{0.17em} cm}}}$) is the drive pulley, and it rotates at.${\mathbf{\text{10 \hspace{0.17em}rad/s}}}$ Pulley B (radius${\mathbf{\text{10 \hspace{0.17em}cm}}}$) is connected by belt ${\mathbf{1}}$ to pulley A. Pulley B’ (radius${\mathbf{\text{5 \hspace{0.17em}cm}}}$) is concentric with pulley B and is rigidly attached to it. Pulley C (radius${\mathbf{\text{25 \hspace{0.17em}cm}}}$) is connected by belt ${\mathbf{2}}$ to pulley B’. Calculate (a) the linear speed of a point on belt ${\mathbf{1}}$, (b) the angularspeed of pulley B, (c) the angular speed of pulley B’, (d) the linear speed of a point on belt${\mathbf{2}}$ , and (e) the angular speed of pulley C. (Hint: If the belt between two pulleys does not slip, the linear speeds at the rims of the two pulleys must be equal.) a) Linear speed of a point on belt $1$ is $1.5\text{\hspace{0.17em}m/s}$.

b) Angular speed of$B$ pulley is $15\text{\hspace{0.17em}rad/s}$.

c) Angular speed of pulley B’ is$15\text{\hspace{0.17em}rad/s}$ .

d) Linear speed of point on belt 2 is$0.75\text{\hspace{0.17em}}\text{m/s}$ .

e) Angular speed of pulley C is $3\text{\hspace{0.17em}rad/s}$.

See the step by step solution

## Step 1: Given

1. Radius of pulley A is ${r}_{a}=15\text{\hspace{0.17em}cm}$
2. Radius of pulley B is ${r}_{b}=10\text{\hspace{0.17em}}\text{cm}$
3. Radius of pulley B’ is ${r}_{{b}^{\text{'}}}=5\text{\hspace{0.17em}cm}$
4. Radius of pulley C is ${r}_{c}=25\text{\hspace{0.17em}}\text{cm}$
5. Angular velocity of pulley A is ${\omega }_{a}=10\text{\hspace{0.17em}rad/s}$
6. If the belt between two pulleys does not slip, the linear speed at the rims of the two pulleys must be equal.

## Step 2: The concept

The linear velocity is given as the rate of change of displacement with respect to time. The angular velocity is defined as the rate of change of angular displacement with respect to time. Find the linearvelocity of belt 1 from radius of pulley A and angular speed of pulley A. From linear speed of belt 1, find the remaining values.

The relation between linear and angular velocity is-

${\mathbf{v}}{\mathbf{=}}{\mathbf{r\omega }}$

where, v is velocity, r is radius and${\mathbf{\omega }}$ is angular velocity.

## Step 3: (a) Determining the linear speed of a point on belt 1

Use the following formula to find linear speed,

$\begin{array}{c}{v}_{a}={r}_{a}{\omega }_{a}\\ =0.15\text{\hspace{0.17em}m}×10\text{\hspace{0.17em}rad}/\text{s}\\ =1.5\text{\hspace{0.17em}}\text{m/s}\end{array}$

Hence, linear speed of a point on belt $1$ is$1.5\text{\hspace{0.17em}m/s}$ .

## Step 4: (b) Determining the angular speed of pulley B

Linear speed of pulley B is also $1.5\text{\hspace{0.17em}m}/\text{s}$ because the belt doesn’t slip.

So, angular speed is given as follows:

$\begin{array}{c}{\omega }_{b}=\frac{{v}_{b}}{{r}_{b}}\\ =\frac{1.5\text{\hspace{0.17em}m}/\text{s}}{0.10\text{\hspace{0.17em}m}}\\ =15\text{\hspace{0.17em}rad/s}\end{array}$

Hence, angular speed of pulley$\text{B}$ is $15\text{\hspace{0.17em}rad/s}$.

## Step 4: (c) Determining the angular speed of pulley B'

Angular speed of pulley $\text{B'}$ is also $15\text{\hspace{0.17em}}\text{rad/s}$ because it is concentric to pulley A.

Hence, angular speed of pulley B’ is$15\text{\hspace{0.17em}}\text{rad/s}$ .

## Step 4: (d) Determining the linear speed of point on belt 2

Linear speed is given as follows:

$\begin{array}{c}{v}_{2}={r}_{{b}^{\text{'}}}×{\omega }_{{b}^{\text{'}}}\\ =0.05\text{\hspace{0.17em}m}×15\text{\hspace{0.17em}rad}/\text{s}\\ =0.75\text{\hspace{0.17em}m/s}\end{array}$

Hence, linear speed of point on belt 2 is $0.75\text{\hspace{0.17em}}\text{m/s}$.

## Step 4: (e) Determining the angular speed of pulley c

Angular speed is as follows:

$\begin{array}{c}{\omega }_{c}=\frac{{v}_{2}}{{r}_{c}}\\ =\frac{0.75\text{\hspace{0.17em}m}/\text{s}}{0.25\text{\hspace{0.17em}m}}\\ =3\text{rad/s}\end{array}$

Hence, angular speed of pulley C is $3\text{\hspace{0.17em}rad/s}$$3\text{\hspace{0.17em}rad/s}$.

## Recommended explanations on Physics Textbooks

94% of StudySmarter users get better grades. 