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Fundamentals Of Physics
Found in: Page 294

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Short Answer

A pulley wheel that is 8.0  cm in diameter has a 5.6 m long cord wrapped around its periphery. Starting from rest, the wheel is given a constant angular acceleration of 1.5 rad/s2 . (a) Through what angle must the wheel turn for the cord to unwind completely? (b) How long will this take?

a) The angle that the wheel must turn for the cord to unwind completely is .140 rad

b) Time taken by wheel to turn for the cord to unwind completelyis.14 sec

See the step by step solution

Step by Step Solution

Step 1: Given

i) Diameter of pulley is D=8.0 cm,

ii) Length of cord is L=5.6 m,

iii) Angular acceleration is α=1.5 rad/ s2,

Step 2: Determining the concept

Find the circumference of the wheel. Using circumference and length of cord, find the number of revolutions. Find the angle using the revolutions. Then, use rotational kinematic equations to find the time.

The circumference of the pulley,

c=πd

The number of revolutions made,

θ=2πn

Total angular distance travelled,

θ=2πn

Relation between angular distance and time taken,

θ=ω0t+12αt2

where, Iisthe moment of inertia, M, m are masses, r is radius, t is time taken.

Step 3: (a) Determining the angle must the wheel turn for the cord to unwind completely

Circumference of wheel is c,

c=πd

c=π×0.08 m

c=0.25 m

Now, number of revolutions n as follows:

n=Length of cordcircumference of wheel

n=5.6 m0.25 m

n=22.3 revolutions

Now, angle is as follows:

θ=2πn

θ=2π×22.3

θ=140 rad

Hence,the angle that the wheel must turn for the cord to unwind completely is 140 rad.

Step 4: (b) Determining how long wheel turn for the cord to unwind completely

Now, time can be calculated using the equation-

θ=ω0×t+12αt2

140 rad=0×t+12×1.5 m/s2×t2

t=13.7 sec

In two significant figures,

t=14 s

Hence, time taken by wheel to turn for the cord to unwind completelyis 14  sec.

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