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Expert-verifiedFigure 10-33 gives angular speed versus time for a thin rod that rotates around one end. The scale on the v axis is set by (a) What is the magnitude of the rod’s angular acceleration? (b) At t = 4.0s , the rod has a rotational kinetic energy of 1.60J. What is its kinetic energy at t = 0 ?
By using the concept of Angular acceleration, Rotational kinetic energy and moment of inertia we can find angular acceleration and rotational kinetic energy at t = 0 s. The formulas used for the concept are given below.
From the graph,
At,
And,
Angular acceleration is the rate of change of angular velocity.
Using all the values,
Hence the value of angular acceleration is, 1.5rad/s2.
Now to solve part b, we will calculate the inertia of the thin rod using rotational kinetic energy
Rearranging rotational kinetic energy formula for inertia I
We have
Rotational inertia of the thin rod (I) is 0.2kh.m2 , we will use this to find rotational kinetic energy at,
Hence the kinetic energy of the thin rod at t = 0 is 0.4J.
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