When the temperature of a metal cylinder is raised from , its length increases by 0.23%
(a) Find the percent change in density.
(b) What is the metal? Use Table.
Temperature of the cylinder changes from 0oC to 100oC and its length increases by 0.23%.
When an object's temperature changes, it expands and grows larger, a process known as thermal expansion. By using the formula for density, we can find the percent change in density. Also, we can use the concept of linear expansion to find the linear expansion coefficient.
The density of a body, …(i)
The linear expansion of a body, data-custom-editor="chemistry" …(ii)
Where data-custom-editor="chemistry" is the coefficient of linear expansion of body, L is length, data-custom-editor="chemistry" is change in temperature, m is mass and V is volume
By differentiating equation (i), we can get
But we know the relation of expansion of volume and length, that is:
Therefore, substituting the above value in equation (a), we get
Where is the percent change in length which is 0.23%
So, the percent change in density is given as:
Hence, the value of percent change in density is -0.69%
The coefficient of thermal expansion can tell us which metal it is. So, we have to find the coefficient of thermal expansion from equation (ii) as follows:
From this value of the coefficient of thermal expansion, we can conclude that the given metal is aluminum.
4 continued: Graphs b through f of Fig. 18-25 is additional sketches of T versus t, of which one or more are impossible to produce. (a) Which is impossible and why? (b) In the possible ones, is the equilibrium temperature above, below, or at the freezing point of water? (c) As the possible situations reach equilibrium, does the liquid partly freeze, fully freeze, or undergo no freezing? Does the ice partly melt, fully melt, or undergo no melting?
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