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2CP

Expert-verifiedFound in: Page 136

Book edition
4th edition

Author(s)
Ruth W. Chabay, Bruce A. Sherwood

Pages
1135 pages

ISBN
9781118875865

**Approximately what is the radius of a copper atom? Is it ${\mathbf{1}}{\mathbf{\times}}{{\mathbf{10}}}^{\mathbf{-}\mathbf{15}}{\mathbf{}}{\mathbf{m}}$, ${\mathbf{1}}{\mathbf{\times}}{{\mathbf{10}}}^{\mathbf{-}\mathbf{12}}{\mathbf{}}{\mathbf{m}}$, ${\mathbf{1}}{\mathbf{\times}}{{\mathbf{10}}}^{\mathbf{-}\mathbf{10}}{\mathbf{}}{\mathbf{m}}$, ${\mathbf{1}}{\mathbf{\times}}{{\mathbf{10}}}^{\mathbf{-}\mathbf{8}}{\mathbf{}}{\mathbf{m}}$, or ${\mathbf{1}}{\mathbf{\times}}{{\mathbf{10}}}^{\mathbf{-}\mathbf{6}}{\mathbf{}}{\mathbf{m}}$ ?**

The approximate radius of a copper atom is **${1}{\times}{{10}}^{-8}{}{\mathrm{m}}$**.

The given atom is the copper atom.

**We need to find the radius for the copper atom and that too in the proximity of the given values.**

The radius of a copper atom can be calculated as,

$\begin{array}{rcl}{128}{}{\mathrm{pm}}& {=}& {128}{}{\mathrm{pm}}{.}\left(1\mathrm{pm}\times \frac{1\mathrm{m}}{{10}^{12}\mathrm{pm}}\right)\\ & {=}& {1}{.}{28}{\times}{{10}}^{-10}{\mathrm{m}}\end{array}$

From equation (I), the approximate radius of a copper atom can be calculated as,

$1.28\times {10}^{-10}\mathrm{m}\approx 1\times {10}^{-10}\mathrm{m}$

Thus, the approximate radius is $1\times {10}^{-10}\mathrm{m}$.

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