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Chapter 5: Determining Forces From Motion

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Matter & Interactions
Pages: 173 - 214

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64 Questions for Chapter 5: Determining Forces From Motion

  1. Question: A student said, "When the Moon goes around the Earth, there is an inward force due to the Moon and an outward force due to centrifugal force, so the net force on the Moon is zero." Give two or more physics reasons why this is wrong.

    Found on Page 206
  2. Question: Tarzan swings back and forth on a vine. At the microscopic level, why is the tension force on Tarzan by the vine greater than it would be if he were hanging motionless?

    Found on Page 206
  3. A ball of mass 450 g hangs from a spring whose stiffness is 110N/m. A string is attached to the ball and you are pulling the string to the right, so that the ball hangs motionless, as shown in Figure. In this situation the spring is stretched, and its length is15 cm. What would be the relaxed length of the spring, if it were detached from the ball and laid on a table?

    Found on Page 207
  4. An800kgload is suspended as shown in Figure 5.69. (a) Calculate the tension in all three wires (that is, the magnitude of the tension force exerted by each of these wires). (b) These wires are made of a material whose value for Young’s modulus is 1.3×1011N/m2. The diameter of the wires is 1.1m. What is the strain (fractional stretch) in each wire?

    Found on Page 207
  5. In Figure 5.72 m1=12 kgand m2=5 kg. The kinetic coefficient of friction between m1and the floor is 0.3and that between m2and the floor is 0.5. You push with a force of magnitude F=110 N. (a) What is the acceleration of the center of mass? (b) What is the magnitude of the force that m1exerts on m2?

    Found on Page 208
  6. The radius of a merry-go round is 11m, and it takes 12s to go around one. What is the speed of an atom in the outer rim?

    Found on Page 208
  7. If the radius of a merry-go-round is5m, and it takes14sto go around once, what is the speed of an atom at the outer rim? What is the direction of the velocity of this atom: toward the center, away from the center, or tangential?

    Found on Page 208
  8. At a particular instant the magnitude of the momentum of a planet is 2.3×1029kg.m/s, and the force exerted on it by the star it is orbiting is 8.9×1022N. The angle between the planet's momentum and the gravitational force exerted by the star is 123°.

    Found on Page 208
  9. The angle between the gravitational force on a planet by a star and the momentum of the planet is 61°at a particular instant. At this instant the magnitude of the planet’s momentum isrole="math" localid="1654013162020" 3.1×1029kgm/s, and the magnitude of the gravitational force on the planet is role="math" localid="1654013174728" 1.8×1023N. (a) What is the parallel component of the force on the planet by the star? (b) What will be the magnitude of the planet’s momentum after 8h?

    Found on Page 208
  10. The angle between the gravitational force on a planet by a star and the momentum of the planet is 61at a particular instant. At this instant the magnitude of the planet’s momentum is 3.1×1029kgm/s, and the magnitude of the gravitational force on the planet is 1.8×1023N. (a) What is the parallel component of the force on the planet by the star? (b) What will be the magnitude of the planet’s momentum after 8h?

    Found on Page 208

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