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1CQ

Expert-verifiedFound in: Page 413

Book edition
2nd Edition

Author(s)
Randy Harris

Pages
633 pages

ISBN
9780805303087

**The left diagram in FIGURE 10.1 might represent a two atom crystal with two bands. Basing your argument on the kinetic energy inside either individual well, explain why both energies in the lower band should be roughly equal to that of the $n=1$ atomic state and why both energies in the upper should roughly equal that of the $n=2$ atomic state**

Both energies in the lower band should be roughly equal to that of $n=1$ atomic state because the two $n=2$ atomic states have the same kinetic energy, the linear combination of these states will also have the same energy as of $n=2$ state.

For an individual well, the kinetic energy of an electron for $n=1$ atomic state or $n=2$ atomic state is a fixed number. When there are two wells, there are two atomic states at $n=1$ or $n=2$.

An electron at $n=2$ molecular state has large separation, and so converges to the addition or subtraction of the two $n=2$ atomic states. Since the two $n=2$ atomic states have the same kinetic energy, the linear combination of these two states will also have the same energy as that of $n=2$ atomic state.

Hence, an electron at $n=1$ molecular state has small separation, and so the energy of the molecular state is only roughly equal to energy for $n=1$ atomic state.

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