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Q69E

Expert-verifiedFound in: Page 191

Book edition
2nd Edition

Author(s)
Randy Harris

Pages
633 pages

ISBN
9780805303087

**does the wave function have a well-defined momentum? Explain.**

The constant in the front multiplies the initial function and two opposing moving plane waves are added, so the momentum is not clearly defined.

** **

- The wave function is

**The eigenvectors of a linear transformation are those vectors where the transformation only modifies the magnitude of the vectors and not the angle. The "eigenvalue" of vectors refers to the ratio by which they differ from the original, and the vectors it works with are referred to as the "eigenvectors" corresponding to the eigenvalue.**

The momentum operator is:

Replace the value of the wave function in the above equation.

Hence, the constant in the front multiplies the initial functionand two opposing moving plane waves are added, so the momentum is not clearly defined.

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