Book edition 2nd Edition

Author(s) Randy Harris

Pages 633 pages

ISBN 9780805303087

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Short Answer

The electron mentioned in Section 12.3 for deep inelastic scattering experiments is $20 GeV$ , and the momentum is given as . $20 GeV / c$ Why so simple a conversion?

The momentum is given as is proved as the conversion is simple. $20 GeV$

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 2: Concept of Energy momentum relationship

The energy of the photon in terms of the speed of light $c$ and momentum $p$ is given as,

. $E = pc$

The relation between the electron's energy and its momentum is so simple is because the electron is moving so fast that we can consider it is a relativistic particle.

Actually, it is moving so fast that its energy from its rest mass is negligible, and we can use the energy-momentum relationship for massless particles, which is:

$E = pc$

Step 3: Explanation of free electron with 20 GeV

Rearrange the above equation for $p$ .

$p = \frac{E}{c}$

Thus, an electron with $20 GeV$ then its momentum is given as, $p = \frac{20 GeV}{c}$ .

The momentum is given as $P = \frac{20 GeV}{c}$ is proved as the conversion is simple.

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Modern Physics

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Short Answer

The electron mentioned in Section 12.3 for deep inelastic scattering experiments is $20 GeV$ , and the momentum is given as . $20 GeV / c$ Why so simple a conversion?

Step by Step Solution

Step 2: Concept of Energy momentum relationship

Step 3: Explanation of free electron with 20 GeV

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Modern Physics

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Short Answer

The electron mentioned in Section 12.3 for deep inelastic scattering experiments is 20GeV , and the momentum is given as .20 GeV/c Why so simple a conversion?

Step by Step Solution

Step 2: Concept of Energy momentum relationship

Step 3: Explanation of free electron with 20 GeV

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The electron mentioned in Section 12.3 for deep inelastic scattering experiments is $20 GeV$ , and the momentum is given as . $20 GeV / c$ Why so simple a conversion?