Q. 15

Expert-verified
Found in: Page 511

### Physics for Scientists and Engineers: A Strategic Approach with Modern Physics

Book edition 4th
Author(s) Randall D. Knight
Pages 1240 pages
ISBN 9780133942651

# A surveyor has a steel measuring tape that is calibrated to be 100.000 m long (i.e., accurate to) at . If she measures the distance between two stakes to be 65.175 m on a day, does she need to add or subtract a correction factor to get the true distance? How large, in mm, is the correction factor?

She needs to subtract a correction factor to get the true distance and the correction factor is mm is 12.18 mm

See the step by step solution

## Step 1: Description

The process of thermal expansion occurs when objects are heated as well as expanded. In case the temperature of an object changes through , as well as length changes through and the length's fractional changes are effective to the temperature's change

## Step 2: Result on findings

The process of thermal expansion occurs when objects are heated as well as expanded. In case the temperature of an object changes through , as well as length changes through and the length's fractional changes are effective to the temperature's change .

The equation (18.8) in the form is:

(1)

In this case, is the coefficient. Table 18.4 effectively gives the coefficient expression of linear for common materials, for instance

The equation for is

(2)

In this case, the subject of L is the initial length and the temperature effectively changes from

Therefore, the change is temperature is

Thus, plug the value for into equation 2 in order to get

There is a requirement for subtracting the correction factor in terms of getting true distance and the correction factor is same for change in length.

Therefore, correction factor