Q. 43

Expert-verifiedFound in: Page 512

Book edition
4th

Author(s)
Randall D. Knight

Pages
1240 pages

ISBN
9780133942651

A brass ring with inner diameter 2.00 cm and outer diameter 3.00 cm needs to fit over a 2.00-cm-diameter steel rod, but at 20C the hole through the brass ring is 50 mm too small in diameter. To what temperature, in C, must the rod and ring be heated so that the ring just barely slips over the rod?

The accurate temperature is

A brass ring with inner diameter 2.00 cm and outer diameter 3.00 cm needs to fit over a 2.00-cm-diameter steel rod, but at 20C the hole through the brass ring is 50 mm too small in diameter.

In increasing the length of the circumference, the requirement for is

There is a matter of change in length of part with linear coefficient would be

Thus, the necessary temperature difference should be

Thus, there can be a replacement of the circumference in both the numerator and denominator and find

Thus, the substitution of numerics in order to find is:

Therefore, in the rod and ring be heated so that the ring just barely slips over the rod.

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