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Q. 33

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Physics for Scientists and Engineers: A Strategic Approach with Modern Physics
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Short Answer

For the circuit of figure ,

a. What is the resonance frequency, in both and ?

b. Find and at resonance.

c. How can be larger than? Explain .

(a) Resonance frequency in =

Resonance frequency in =

(b)At resonance,

(c) See explanation below .

See the step by step solution

Step by Step Solution

Part(a) Step1: Given information.

We have given,

We have to find resonance frequency in rad/s() and Hz.

Part(a) Step2: Simplify.

We know at resonance condition ,the frequency is;

We know ,

Part(b) Step1: Given information.

We have given,

We have to find and .

Part(b) Step2: Simplify.

Firstly we need to find ,

At resonance, I is maximum and equal to ,

now,

Also,

Part(c) Step1: Given information.

We have given and.

We have to explain how can be larger than.

Part(c) Step2: Explanation.

If the circuit is in resonance condition , the peak to peak voltages on capacitor and the inductor can be larger than the peak to peak voltage .

Also'

( )

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