The current lags the emf by in a series RLC circuit with and . What is the peak current through the circuit?
Peak current through RLC circuit is,
We are given that,
Peak voltage is,
Phase difference is,
Let inductive reactance is,
And capacitive reactance is,
We know that,
Therefore, Impedance is,
Hence Peak current is,
II An electric circuit, whether it's a simple lightbulb or a complex amplifier, has two input terminals that are connected to the two output terminals of the voltage source. The impedance between the two input terminals (often a function of frequency) is the circuit's input impedance. Most circuits are designed to have a large input impedance. To see why, suppose you need to amplify the output of a high-pass filter that is constructed with a resistor and a capacitor. The amplifier you've chosen has a purely resistive input impedance. For a signal, what is the ratio of the filter's peak voltage output with (load) and without (no load) the amplifier connected if the amplifier's input impedance is (a) and (b) ?
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