Suggested languages for you:

Q. 70

Expert-verified
Found in: Page 158

### Physics for Scientists and Engineers: A Strategic Approach with Modern Physics

Book edition 4th
Author(s) Randall D. Knight
Pages 1240 pages
ISBN 9780133942651

# .a. Write a realistic problem for which these are the correct equations.b. Draw the free-body diagram and the pictorial representation for your problem.c. Finish the solution of the problem.

Part (a): A block of mass is kept on another block which is moving with acceleration .The coefficient of static friction between the surface of the block is . Calculate the maximum possible acceleration for which the upper block will not slide.

Part (b): The free body diagram for the equation is,

Part (c): Calculated value for and from the two given equations are and .

See the step by step solution

## Part (a) Step 2: Explanation of solution

The above equations, and can be represented by the normal force applied to the upper block and acceleration of the lower block.

The first equation represents the equilibrium between the frictional force between the surface and the applied force on the lower block. If the applied force is greater than the frictional force between the surface, then the upper block will slide. Knowing from the second equation, calculated from this equation.

The second equation represents the equilibrium between the weight of the upper block and the normal reaction on the upper block. From this equation, we can calculate the normal reaction.

A block of mass is kept on another block which is moving with acceleration .The coefficient of static friction between the surface of the block is . Calculate the maximum possible acceleration for which the upper block will not slide.

## Part (b) Step 3: Given equation

The given equations are:

## Part (b) Step 4: Free body diagram with explanation.

The free body diagram, represents the force applied on the block by the lower block, and represents the frictional force applied to the upper block. The other two forces are is the weight of the block and is the normal reaction, which is equal to the weight of the block.

Since the block is in equilibrium, we must have And .

## Part (c) Step 6: Calculation.

Solve second equation to calculate .

Now, substitute of the value of in the first equation to calculate the value of .