Q.14

Expert-verified
Found in: Page 153

### Physics for Scientists and Engineers: A Strategic Approach with Modern Physics

Book edition 4th
Author(s) Randall D. Knight
Pages 1240 pages
ISBN 9780133942651

# Suppose you push a hockey puck of mass m across frictionless ice for 1.0 s, starting from rest, giving the puck speed v after traveling distance d. If you repeat the experiment with a puck of mass 2m, pushing with the same force, a. How long will you have to push for the puck to reach the same speed v? b. How long will you have to push for the puck to travel the same distance d?

(a) Puck takes twice as long as puck mass to reach the same speed .

(b) As a result, the puck takes a long time. to travel the distance is times the amount of time it takes for a puck to go a certain distance .

See the step by step solution

## Step 1: Introduction

The kinematic equation for motion along a straight line is as follows:-axis ,

We is the highest possible velocity is the beginning speed, is the acceleration and is the time interval.

The following is the kinematics expression for distance travelled:

By all above is the final position and initial position of the puck.

## Step 2: Explanation (a)

For mass puck , the formulation of Newton's second rule of motion is as follows,

Rearrange the phrase of Newton's second law of motion to find the value of acceleration.,

The time it takes for the puck to reach the specified velocity is calculated as follows,

Calculation of the time required by mass puck A to reach the speed is as follows,

Putting for for for and for in the kinematics equation,

&

For mass puck B, the formulation of Newton's second equation of motion is as follows,

To calculate the value of acceleration, rearrange the phrase of Newton's second law of motion,

The amount of time it takes for the puck to attain the desired speed is calculated as follows,

Calculation of the time required by mass puck B to reach the speed is as follows,

Putting for for for and for in the kinematics equation,

Putting for from the expression of time of puck A of mass ,

As a result, puck B takes twice as long to reach the same speed as puck mass.

## Step 3: Explanation (b)

Calculate the amount of time puck of mass takes to travel is as follows,

Putting for for for and for in the kinematics equation,

Calculation of the time required by mass puck B is as follows, Putting for for for and for in the kinematics equation,

Putting for from the mass puck A statement of time ,

As a result, the puck spends more time on the ice to travel a considerable distance is times and time taken by the puck's mass .