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Q.42

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Found in: Page 156

### Physics for Scientists and Engineers: A Strategic Approach with Modern Physics

Book edition 4th
Author(s) Randall D. Knight
Pages 1240 pages
ISBN 9780133942651

# Seat belts and air bags save lives by reducing the forces exerted on the driver and passengers in an automobile collision. Cars are designed with a “crumple zone” in the front of the car. In the event of an impact, the passenger compartment decelerates over a distance of about 1 m as the front of the car crumples. An occupant restrained by seat belts and air bags decelerates with the car. By contrast, an unrestrained occupant keeps moving forward with no loss of speed (Newton’s first law!) until hitting the dashboard or windshield. These are unyielding surfaces, and the unfortunate occupant then decelerates over a distance of only about 5 mm. a. A 60 kg person is in a head-on collision. The car’s speed at impact is 15 m/s. Estimate the net force on the person if he or she is wearing a seat belt and if the air bag deploys. b. Estimate the net force that ultimately stops the person if he or she is not restrained by a seat belt or air bag.

Newton's first law - Every body in this universe remains in the state of rest or motion until or unless an external force is applied on it.

See the step by step solution

## Step 1 : Given

Mass of person, m =60kg

Initial speed of car, u = 15m/s

Distance with seat belt,=1m

Distance without seatbelt,=5mm=0.005m

Finial speed, v = 0

## Step 2 : Explanation

a.

Using =+2as,

0 = +2a(1)

a = = -112.5

Using Newton's second law. F = m.a

= (60)(112.5) = 6750 N

Therefore, net force on the person is 6750 N

## Step 3 : Explanation

b.

Using =+2as,

0 = +2a(0.005)

a = = -22500

Using newton's second law, F = ma,

= (60)(22500) = 1350000 N

The net force that ultimately stops the person if he or she is not restrained by a seat belt or air bag is 1350000 N.