An elevator, hanging from a single cable, moves upward at constant speed. Friction and air resistance are negligible. Is the tension in the cable greater than, less than, or equal to the gravitational force on the elevator? Explain. Include a free-body diagram as part of your explanation.
An elevator on a single cable moves steadily upward until the cable's tension equals the elevator's gravitational pull.
(1) Tension force in the upwards-pointing orientation of the cable.
(2) Gravitational force a force acting on a vertically downward-pointing elevator.
The diagram is represented as:
We can write the expressions as :
When the elevator is travelling at a constant pace in the upward direction, it is said to be accelerating
When an elevator is travelling higher, the forces operating on the elevator are as follows:(1) The cable has a tension force pointing up.(2) Gravitational force the cable has a tension force pointing up.
As a result, an elevator suspended on a single cable climbs upward at a constant pace, and the tension force in the cable equals the elevator's gravitational pull.
An object moving in a liquid experiences a linear drag force: , direction opposite to the motion), where is a constant called the drag coefficient. For a sphere of radius the drag constant can be computed as , where is the viscosity of the liquid.
a. Find an algebraic expression for , the -component as a function of time, for a spherical particle of radius and mass that is shot horizontally with initial speed through a liquid of viscosity .
b. Water at has viscosity . Suppose a -diameter, ball is shot horizontally into a tank of water. How long will it take for the horizontal speed to decrease to of its initial value?
Five balls move through the air as shown in FIGURE Q6.17 All five have the same size and shape. Air resistance is not negligible. Rank in order, from largest to smallest, the magnitudes of the accelerations aa to ae. Some may be equal. Give your answer in the form and explain your ranking.
An accident victim with a broken leg is being placed traction. The patient wears a special boot with a pulley attached to the sole. The foot and boot together have a mass of 4.0 kg and the doctor has decided to hang a 6.0 kg mass from the rope. The boot is held suspended by the ropes, as shown in FIGURE P6.41, and does not touch the bed a. Determine the amount of tension in the rope by using Newton’s laws to analyze the hanging mass. b. The net traction force needs to pull straight out on the leg. What is the proper angle u for the upper rope? c. What is the net traction force pulling on the leg? Hint: If the pulleys are frictionless, which we will assume, the tension in the rope is constant from one end to the other.
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