Q. 62

Expert-verifiedFound in: Page 202

Book edition
4th

Author(s)
Randall D. Knight

Pages
1240 pages

ISBN
9780133942651

A 500 g steel block rotates on a steel table while attached to a 2.0-m-long massless rod. Compressed air fed through the rod is ejected from a nozzle on the back of the block, exerting a thrust force of 3.5 N. The nozzle is 70^{o} from the radial line, as shown in FIGURE P8.62. The block starts from rest. a. What is the block’s angular velocity after 10 rev? b. What is the tension in the rod after 10 rev?

a) Block’s angular velocity after 10 rev is 20.33 rad/sec or 194.1372 rpm

b) Tension in the rod after 10 rev is T=412.111 N

Mass of block = 500 g =0.5 kg

Length of rod = 2 m Thrust force = 3.5 N.The nozzle is at an angle of 70^{o} from the radial line as shown. The block starts from rest

The centripetal force is calculated by

mv^{2}/r ……………………..(1)

The angular velocity of the mass revolving around a circle is calculated by

Now break the thrust in tangential and radial components

Now find angular acceleration of the block

Substitute values

Substitute in equation (2) to get angular velocity after 10 rev

Mass of block = 500 g =0.5 kg

Length of rod = 2 m Thrust force = 3.5 N.The nozzle is at an angle of 70^{o} from the radial line as shown. The block starts from rest.

The centripetal force acting on the block is calculated by substituting values in equation (1)

substitute v= ωr

Tension in the rod after 10 rev is

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